Yeah, since t(N) < N, you can use the decomposition for N! and one extra factor ... | Hacker News

Hacker Newsnew | past | comments | ask | show | jobs | submit

		intuitionist 11 months ago \| parent \| context \| favorite \| on: Decomposing a Factorial into Large Factors Yeah, since t(N) < N, you can use the decomposition for N! and one extra factor (N+1) to get a decomposition for (N+1)! with a smallest part equal to t(N).

zahlman 11 months ago [–]

Oh, that's much easier than I thought it would be. Nice job being rigorous, too.

Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact